#include <stdio.h>

int main( int argc, char* argv[] ) {

    int z;
    unsigned int m;
    char firstLetter;
    char* word;

    printf("Enter the following (adding spaces as needed)\n");
    printf("int, unsigned-int, char, and a string/word\n");
    scanf("%d %u %c%s", &z, &m, &firstLetter, &(*word));

    printf("Got:\n%d %u %c and %s\n", z, m, firstLetter, word);
    return 0;
    }

/* Question: Why write "&*word" -- don't the & and the * cancel out?"
 * Yes, they do.  You can get rid of both of them, and the program runs exactly the same.
 * BUT they are there for humans:
 * the * is there because I'm thinking of *word as being my string.
 * And the '&' is in front of *word, because I'm telling the reader
 * "Hey, be aware that the contents of my local var might get changed 
 *  by the function I'm calling!"
 * Which is how the '&' in front of `n` and `firstLetter` also are meant.
 */